Simultaneous equations with one linear and one non-linear equation might... Show more
Solving Linear and Non-Linear Simultaneous Equations

Solving One Linear and One Non-Linear Simultaneous Equation
When you've got simultaneous equations where one is linear (straight line) and one is non-linear (like a circle or parabola), substitution is your best mate. The process is straightforward: rearrange the linear equation to make one variable the subject, then substitute this into the non-linear equation.
Let's look at the example: x² + y² = 25 (this is a circle) and x + y = 7 (this is a straight line). First, rearrange the linear equation to get y = 7 - x. This gives you y in terms of x.
Next, substitute this expression into the non-linear equation: x² + ² = 25. Expand the brackets carefully: x² + 49 - 14x + x² = 25. Simplify to get 2x² - 14x + 24 = 0.
Now solve this quadratic using the formula or factoring. You'll get x = 4 and x = 3. Substitute back into y = 7 - x to find the corresponding y-values: when x = 4, y = 3, and when x = 3, y = 4. Your solutions are (3,4) and (4,3) - these are the points where the circle and line intersect.
Quick Tip: Always check your answers by substituting both coordinates back into both original equations!
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Solving Linear and Non-Linear Simultaneous Equations
Simultaneous equations with one linear and one non-linear equation might seem tricky, but they're actually quite manageable once you know the method. You'll use substitution to solve these step-by-step, and this skill is essential for your Leaving Cert maths.

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Solving One Linear and One Non-Linear Simultaneous Equation
When you've got simultaneous equations where one is linear (straight line) and one is non-linear (like a circle or parabola), substitution is your best mate. The process is straightforward: rearrange the linear equation to make one variable the subject, then substitute this into the non-linear equation.
Let's look at the example: x² + y² = 25 (this is a circle) and x + y = 7 (this is a straight line). First, rearrange the linear equation to get y = 7 - x. This gives you y in terms of x.
Next, substitute this expression into the non-linear equation: x² + ² = 25. Expand the brackets carefully: x² + 49 - 14x + x² = 25. Simplify to get 2x² - 14x + 24 = 0.
Now solve this quadratic using the formula or factoring. You'll get x = 4 and x = 3. Substitute back into y = 7 - x to find the corresponding y-values: when x = 4, y = 3, and when x = 3, y = 4. Your solutions are (3,4) and (4,3) - these are the points where the circle and line intersect.
Quick Tip: Always check your answers by substituting both coordinates back into both original equations!
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What is the Knowunity AI companion?
Our AI companion is specifically built for the needs of students. Based on the millions of content pieces we have on the platform we can provide truly meaningful and relevant answers to students. But its not only about answers, the companion is even more about guiding students through their daily learning challenges, with personalised study plans, quizzes or content pieces in the chat and 100% personalisation based on the students skills and developments.
Where can I download the Knowunity app?
You can download the app in the Google Play Store and in the Apple App Store.
Is Knowunity really free of charge?
That's right! Enjoy free access to study content, connect with fellow students, and get instant help – all at your fingertips.
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